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12 January, 04:32

you and your friend left a bus terminal at the same time and traveled in opposite directions. Your bus was in heavy traffic and had to travel 20 miles per hour slower than your freind's bus. After 3 hours, the buses were 270 miles apart. How fast was each bus going?

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Answers (2)
  1. 12 January, 05:05
    0
    speed of the two vehicle are 55 mph and 35 mph

    Explanation:

    given,

    speed of friends vehicle = x mph

    speed of your vehicle = (x - 20) mph

    when both travel in opposite direction

    distance between the two buses = 270 miles

    distance = speed * time

    270 = 3 (x) + 3 (x-20)

    90 = 2 x - 20

    x = 55 mph

    now, speed of other vehicle is (55-20) = 35 mph

    hence, speed of the two vehicle are 55 mph and 35 mph
  2. 12 January, 06:17
    0
    The rate at which bus 1 is going is 55 mph

    The rate at which bus 1 is going is 35 mph

    Explanation:

    As per the question:

    Suppose, the distance traveled by Bus 1 be 'd' at the rate R after a time, t = 3h

    Thus

    Suppose, the distance traveled by Bus 1 be 'd'' at the rate, R'20 mph slower than the rate of Bus 1 after the same time.

    R' = R - 20

    The distance is given as the product of rate and time:

    d = Rt (1)

    Now, the total distance given is 270 miles:

    d + d' = 270

    Now, using eqn (1):

    Rt + R't = 270

    3 (R + R - 20) = 270

    6R = 270 + 60

    R = 55 mph

    R' = R - 20 = 55 - 20 = 35 mph
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