A ball is thrown horizontally from a 16 m - high building with a speed of 2.0 m/s.

How far from the base of the building does the ball hit the ground?

3.61 m

Explanation:

First, find how long it takes to land.

Given (in the y direction):

Δy = 16 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(16 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 1.81 s

Given (in the x direction):

v₀ = 2.0 m/s

a = 0 m/s²

t = 1.81 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (2.0 m/s) (1.81 s) + ½ (0 m/s²) (1.81 s) ²

Δx = 3.61 m