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13 May, 03:13

If the current through a resistor is cut in half, how does the power dissipated by the resistor change? (P=0VI=1^ 2 R = V^ 2 R)

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  1. 13 May, 05:32
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    1/4

    Explanation:

    P = IV, and V = IR, so P = I²R.

    If R is held constant, and I is cut in half, then power becomes:

    P = (I/2) ²R

    P = 1/4 I²R

    So the power reduces by a factor of 4.
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