If the current through a resistor is cut in half, how does the power dissipated by the resistor change? (P=0VI=1^ 2 R = V^ 2 R)

Question

Physics

Malachi Berger

13 May, 03:13

If the current through a resistor is cut in half, how does the power dissipated by the resistor change? (P=0VI=1^ 2 R = V^ 2 R)

+4

Answers (1)

Know the Answer?

Isiah Mayo · Answer 1

1/4

Explanation:

P = IV, and V = IR, so P = I²R.

If R is held constant, and I is cut in half, then power becomes:

P = (I/2) ²R

P = 1/4 I²R

So the power reduces by a factor of 4.