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9 February, 15:09

How fast must a 70 kg student be running to have a kinetic energy of 568 J?!

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  1. 9 February, 15:57
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    Answer: 4.03 m/s

    Explanation: Kinetic energy is

    KE = 1/2 m v²

    So we derive the equation to have v.

    v = √ 2KE / m

    = 2 x 568 J / 70 kg

    = 16.23

    = √ 16.23

    = 4.03 m/s
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