Ask Question
9 April, 18:56

Beaker A contains 100 mL of water at a temperature of 25 °C. Beaker B contains 100 mL of water at a temperature of 60 °C. Which of the following statement is true? a. Beaker A has lower kinetic energy than beaker B

b. Beaker A has higher thermal energy than beaker B

c. Beaker A has higher potential energy than beaker B

d. Beaker A has lower potential energy than beaker B

e. Beaker A has higher kinetic energy than beaker B

+5
Answers (1)
  1. 9 April, 20:13
    0
    Only option A is correct. Beaker A has lower kinetic energy than beaker B.

    Explanation:

    Step 1: Data given

    Beaker 1 has a volume of 100 mL at 25 °C

    Beaker B has a volume of 100 mL at 60 °C

    Thermal energy = m*c*T

    Thermal energy beaker A = 100 grams*4.184 * 25°C

    Thermal energy beaker B = 100 grams * 4.184*60°C

    ⇒ Since both beakers contain the same amount of water, the thermal energy depends on the temperature.

    Since beaker B has a higher temperature, it has a higher thermal energy than beaker A

    When we heat a substance, its temperature rises and causes an increase in the kinetic energy of its constituent molecules. Temperature is, in fact, a measure of the kinetic energy of molecules.

    This means beaker B has a higher kinetic energy than beaker A

    Potential energy doesn't depend on temperature. this means the potential energy of beaker A and beaker B is the same.

    a. Beaker A has lower kinetic energy than beaker B. This is correct.

    b. Beaker A has higher thermal energy than beaker B. This is false.

    c. Beaker A has higher potential energy than beaker B. This is false.

    d. Beaker A has lower potential energy than beaker B. This is false

    e. Beaker A has higher kinetic energy than beaker B. This is false.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Beaker A contains 100 mL of water at a temperature of 25 °C. Beaker B contains 100 mL of water at a temperature of 60 °C. Which of the ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers