Ben hit a 0.25kg nail into a wood with a 5.2kg hammer. If the hammer moves witht the speed of 52 m/s and two fifth of its kinetic energy is coverted to the internal energy of the hammber and nail. How much does the total internal. Energy increase

Mass of nails is 0.25kg

Mass of hammer 5.2kg

Speed of hammer is = 52m/s

Then, Ben kinetic energy is given as

K. E = ½mv²

K. E = ½*5.2*52²

K. E = 7030.4J

Given that, two-fifth of kinetic energy is converted to internal energy

Internal energy (I. E) = 2/5 * K. E

Internal energy (I. E) = 2/5 * 7030.4

I. E=2812.16J.

Energy increase is total Kinetic energy - the internal energy

∆Et = K. E-I. E

∆Et = 7030.4 - 2812.16

∆Et = 4218.24J