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4 December, 17:21

Imagine we cook an egg by immersing it into water which is boiled by an electric heater. The heater utilizes a current I = 10 A at a voltage V = 120 volts for a time t = 120 s lf the change in energy of the newly-cooked egg over its raw torm is given by ΔEngg = 28.8 kJ, what is the amount of energy wasted in the process?

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  1. 4 December, 19:46
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    Q' = 115.2 KJ

    Explanation:

    Given that

    Current I = 10 A

    Voltage = 120 V

    Time t = 120 s

    The energy supplied Q = V I t

    Q = 10 x 120 x 120 J

    Q = 144 x 1000 J

    Q = 144 KJ

    The change in the energy ΔEngg = 28.8 kJ

    By using energy conservation

    Q = Q' + ΔEngg

    Q'=Wasted energy

    Now by putting the values in the above equation

    144 = Q' + 28.8 KJ

    Q' = 115.2 KJ

    Therefore the waste energy will be 115 kJ.
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