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9 April, 21:24

At t = 15.0 seconds an object with mass 6 kg was observed to have a velocity of ‹ 9, 25, - 9 › m/s. At t = 15.1 seconds its velocity was ‹ 18, 17, 21 › m/s. What was the average (vector) net force acting on the object?

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  1. 10 April, 01:20
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    Average net force acting on the object is ‹ 540, - 480, 1800 › N

    Explanation:

    Mass = 6 kg

    Initial velocity = ‹ 9, 25, - 9 › m/s

    Initial time = 15.0 s

    Final velocity = ‹ 18, 17, 21 › m/s

    Final time = 15.1

    Change in velocity = ‹ 18, 17, 21 › - ‹ 9, 25, - 9 › = ‹ 9, - 8, 30 › m/s

    Change in time = 15.1 - 15.0 = 0.1 s

    Acceleration = Change in velocity : Change in time

    Acceleration = ‹ 9, - 8, 30 › : 0.1

    Acceleration = ‹ 90, - 80, 300 › m/s²

    Force = Mass x acceleration

    Force = 6 x ‹ 90, - 80, 300 › = ‹ 540, - 480, 1800 › N

    Average net force acting on the object is ‹ 540, - 480, 1800 › N
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