A soccerball is kicked straight out from a hill at 15 m/s and lands 42m away. how tall is the hill

The height of the hill is, h = 38.42 m

Explanation:

Given,

The horizontal velocity of the soccer ball, Vx = 15 m/s

The range of the soccer ball, s = 42 m

The projectile projected from a height is given by the formula

S = Vx [Vy + √ (Vy² + 2gh) ] / g

Therefore,

h = S²g/2Vx² (Since Vy = 0)

Substituting the values

h = 42² x 9.8 / (2 x 15²)

= 38.42 m

Hence, the height of the hill is, h = 38.42 m