If a car accelerates uniformly from rest to 15 meters

per second over a distance of 100 meters, the magnitude of the car's acceleration is

1.125 m/s²

Explanation:

Applying Newton's equation of motion,

v² = u²+2as

Where v = final velocity, u = initial velocity, a = acceleration, s = distance.

Note: u = 0 m/s (from rest)

make a the subject of the equation above.

a = v²/2s ... Equation 2

Given: v = 15 m/s². s = 100 m

Substitute into equation 2

a = 15² / (2*100)

a = 225/200

a = 1.125 m/s²

1.125m/s^2

Explanation:

Since acceleration is defined as the rate of change in velocity with respect to time. Mathematically

v^2 = u^2+2as

Where a, v, u and s are the acceleration, final velocity, initial velocity and distance respectively.

a = ?

u = 0m/s

v = 15m/s

s = 100m

Substituting the values into the formula above

v^2 = u^2+2as

15^2=0^2+2*a*100

225 = 0+200a

225 = 200a

Divide both sides by 200

225/200 = 200a/200

a = 1.125m/s^2

Hence the acceleration of the car is 1.125m/s^2.

Note that the car accelerated uniformly from rest, that was why the initial velocity was 0m/s