If your front lawn is 25.0 feet wide and 20.0 feet long, and each square foot of lawn accumulates 1250 new snowflakes every minute, how much snow, in kilograms, accumulates on your lawn per hour

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Question:

If your front lawn is 25.0 feet wide and 20.0 feet long, and each square foot of lawn accumulates 1250 new snowflakes every minute, how much snow, in kilograms, accumulates on your lawn per hour? Assume an average snow flake has a mass of 1.70 mg.

Given Information:

Area of lawn = 25 ft into 20 ft = 500 ft²

Rate of snowflakes = 1250 per minute

Mass of snowflakes = 1.70 mg = 0.0017 g = 0.0000017 kg

Required Information:

Mass of snowflakes per hour = ?

Answer:

Mass of snowflakes = 63.75 kg

Explanation:

Total snowflakes = Rate of snowflakes*Area of lawn

Total snowflakes = 1250*500

Total snowflakes = 625000/min

Multiply by 60 minutes to convert into hour

Total snowflakes = 625000*60

Total snowflakes = 37500000/hour

Weight of snowflakes = Total snowflakes*Mass of each snowflake

Weight of snowflakes = 37500000*0.0000017

Weight of snowflakes = 63.75 kg

Therefore, there will be 63.75 kg of snowflakes in an area of 500 ft².

The assumption in this answer is that the average mass of snowflake is 3 mg.

Answer:

112.5 kg

Explanation:

In 1 minute, there are 1250 snowflakes per square feet.

In 1 hour, there 1250 * 60 = 75000 snowflakes

1 snowflake has a mass of 3 mg

75000 snowflakes have a mass of 75000 * 3 = 225000 mg

Converting to kg

mass = 225000 : (1000 * 1000) kg = 0.225 kg

This is the mass of snowflakes in 1 square feet.

The area of the lawn = 25.0 ft * 20.0 ft = 500 ft2

For 500 square feet,

mass = 0.225 kg * 500 = 112.5 kg