At 120*C, the pressure of a gas is 107 kPa. What will be the pressure at 205^ * C

Correct answer: p₂ = 182.79 kPa

Explanation:

You forgot to mention that this is an isochoric process ie the volume is constant V = const the formula applies to this process

p₁ / T₁ = p₂ / T₂ where is T₁ = 120⁰C, p₁ = 107 kPa and T₂ = 205⁰C

p₂ = p₁ T₂ / T₁ = 107 · 205 / 120 = 182.79 kPa

p₂ = 182.79 kPa

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