Which of the following has the greatest number of particles A) 1 mole of Na B) 22.990g of Na C) 1 mole of Be D) 9.012 g of Be E) all are the same

E) all are the same

Explanation:

The question requires we identify the amount of an element with the greatest number of particles.

We need to know that 1 mole of an element contains particles equivalent to the Avogadro's number, 6.022 * 10^23. That is, 1 mole of an element = 6.022 * 10^23 particles

In this case;

Choice A

1 mole of Na

1 mole of Na contains 6.022 * 10^23 atoms

Choice B

22.990 g of Na

The molar mass of sodium is 22.99 g/mol

Therefore, 22.990 g of Na contains 6.022 * 10^23 atoms

Choice C

1 mole of Be

1 mole of Be contains 6.022 * 10^23 atoms

Choice D

9.012 g of Be

But, the molar mass of Be is 9.012 g

Thus; 9.012 g of Be contains 6.022 * 10^23 atoms

We can therefore, conclude that all the given choices are the same, they have equal number of particles.