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13 June, 13:44

an 100kg object traveling at 50m/s collides (perfectly inelastic) with a 50kg object initially at rest. what is the sum of the momentum of both objects prior to the collision?

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  1. 13 June, 16:13
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    5000 kg. m/s

    Explanation:

    Before collision, momentum of 100 Kg is given by

    p=mv where p is momentum, m is the mass of object and v is the velocity,

    therefore, the momentum=100*50=5000 kg. m/s

    The momentum of the 50 Kg is zero since it's at rest hence v=o

    Total momentum before collision is therefore 5000+0=5000 kg. m/s
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