Two circular loops of wire, each containing a single turn, have the same radius of 3.40 cm and a common center. The planes of the loops are perpendicular. Each carries a current of 1.80 A. What is the magnitude of the net magnetic field at the common center?

Answer: To solve for the net magnetic field of two circular loops of wire, each containing a single turn

B net = √[ (NUI / 2R) ^2 * (NUI / 2R) ^2]

Where B net = Net magnetic field

B net = √2 * (NUI / 2R)

B net = [ √2 * 1 * (4 * 3.142 * 10^-7) * (1.8) ] : 2 * 0.034

B net = { 1.414 * (0.00000126) * (1.8) }: 0.068

B net = 4.72 * 10^-5 T