A basketball is thrown up into the air. It is released with an initial velocity of 8.5 m/s. How long does it take to get to the top of its motion?

It takes 0.867 seconds to get to the top of its motion

Explanation:

We have equation of motion v = u + at

Initial velocity, u = 8.5 m/s

Final velocity, v = 0 m/s - At maximum height

Time, t = ?

Acceleration, a = - 9.81 m/s²

Substituting

v = u + at

0 = 8.5 + - 9.81 x t

t = 0.867 s

It takes 0.867 seconds to get to the top of its motion

0.87 s

Explanation:

initial velocity, u = 8.5 m/s

Let it takes time t to reach to maximum height. At maximum height the velocity is zero, so, v = 0

Use first equation of motion

v = u - gt

where, g be the acceleration due to gravity

0 = 8.5 - 9.8 t

t = 0.87 s

Thus, the time taken to reach at top is 0.87 s.