An object is dropped from rest from a height of 4.1 107 m above the surface of the Earth. If there is no air resistance, what is its speed when it strikes the Earth

2.83 x 10^4m/s

Explanation:

First, let us calculate the time taken by the object to hit the surface of the earth.

H = 4.1 x 10^7m

g = 9.8m/s2

t = √ (2H/g)

t = √ ((2x 4.1 x 10^7) / 9.8)

t = 2892.64secs

Now, we can find the velocity with which the object strikes the earth as follows:

V = gt

V = 9.8 x 2892.64

V = 2.83 x 10^4m/s