A ball is thrown upwards with an initial velocity of 25. o m/s, what is the velocity of the ball at 11.9 m from the ground?

v2 = 19.79m/s

Explanation:

Okay, lets write down everything we have;

v1 = 25m/s [up]

v2 = ?

d = 11.9 [up]

a = 9.8 [down]

So the formula we will use is v2^2 = v1^2 + 2ad. We also have to make acceleration negative, so everything can have the same direction of up:

v2^2 = v1^2 + 2ad

v2^2 = (25) ^2 + 2 (-9.8) (11.9)

v2^2 = 625 - 233.24

v2^2 = 391.76

v2 = 19.79m/s