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11 January, 11:13

a circular cylinder and isused to maintain a water depth of 4 m. That is, when the water depth exceeds 4 m, thegate opens slightly and lets the water flow under it. Determine the weight of the gate permeter of length

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  1. 11 January, 14:07
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    W / A = 39200 kg / m²

    Explanation:

    For this problem let's use the equilibrium equation of / newton

    F = W

    Where F is the force of the door and W the weight of water

    W = mg

    We use the concept of density

    ρ = m / V

    m = ρ V

    The volume of the water column is

    V = A h

    We replace

    W = ρ A h g

    On the other side the cylinder cover has a pressure

    P = F / A

    F = P A

    We match the two equations

    P A = ρ A h g

    P = ρ g h

    P = 39200 Pa

    The weight of the water column is

    W = 1000 9.8 4 A

    W / A = 39200 kg / m²
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