Ask Question
15 April, 00:18

The difference in potential between the accelerating plates of a T. V. set is about 30 kV. If the distance between these plates is 1.3 cm, find the magnitude of the uniform electric field in this region.

+2
Answers (1)
  1. 15 April, 03:22
    0
    2.31 * 10^6 V/m

    Explanation:

    The relationship between potential difference and electric field is given as:

    V = E * r

    => E = V/r

    V = 30kV = 30000V

    r = 1.3cm = 0.013m

    E = 30000/0.013

    E = 2.31 * 10^6 V/m
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The difference in potential between the accelerating plates of a T. V. set is about 30 kV. If the distance between these plates is 1.3 cm, ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers