Ask Question
31 March, 13:11

A particle with a charge of - 1.24 x 10"° C is moving with instantaneous velocity (4.19 X 104 m/s) î + (-3.85 X 104 m/s) j. What is the force exerted on this particle by a magnetic field (a) = B (1.40 T) i and (b) È = (1.40 T) k?

+2
Answers (1)
  1. 31 March, 16:26
    0
    (a) F = 6.68*10¹¹⁴ N (-k)

    (b) F = (6.68*10¹¹⁴ i + 7.27*10¹¹⁴ j) N

    Explanation

    To find the magnetic force in terms of a fixed amount of charge q that moves at a constant speed v in a uniform magnetic field B we apply the following formula:

    F=q * v X B Formula (1)

    q: charge (C)

    v: velocity (m/s)

    B: magnetic field (T)

    vXB : cross product between the velocity vector and the magnetic field vector

    Data

    q = - 1.24 * 10¹¹⁰ C

    v = (4.19 * 10⁴ m/s) î + (-3.85 * 10⁴m/s) j

    B = (1.40 T) i

    B = (1.40 T) k

    Problem development

    a) vXB = (4.19 * 10⁴ m/s) î + (-3.85 * 10⁴m/s) j X (1.40 T) i =

    = - (-3.85*1.4) k = 5.39 * 10⁴ m/s*T (k)

    1T = 1 N / C*m/s

    We apply the formula (1)

    F = 1.24 * 10¹¹⁰ C * 5.39 * 10⁴ m/s * N / C*m/s (-k)

    F = 6.68*10¹¹⁴ N (-k)

    a) vXB = (4.19 * 10⁴ m/s) î + (-3.85 * 10⁴m/s) j X (1.40 T) k =

    = ( - 5.39 * 10⁴i - 5.87 * 10⁴j) m/s*T

    1T = 1 N / C*m/s

    We apply the formula (1)

    F = 1.24 * 10¹¹⁰ C * (5.39 * 10⁴i + 5.87 * 10⁴j) m/s * N / C*m/s

    F = (6.68*10¹¹⁴ i + 7.27*10¹¹⁴ j) N
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A particle with a charge of - 1.24 x 10"° C is moving with instantaneous velocity (4.19 X 104 m/s) î + (-3.85 X 104 m/s) j. What is the ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers