A car traveling at 25m/sec, stops in 0.103 km. what is the deceleration provided by the brakes?

-3.03 m/s²

Explanation:

v² = v₀² + 2a (x - x₀)

where v is the final velocity,

v₀ is the initial velocity,

a is the acceleration,

x is the final position,

and x₀ is the initial position.

Given:

v = 0 m/s

v₀ = 25 m/s

x = 103 m

x₀ = 0 m

Find: a

v² = v₀² + 2a (x - x₀)

(0 m/s) ² = (25 m/s) ² + 2a (103 m - 0 m)

a = - 3.03 m/s²

Round as needed.