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15 July, 13:57

The force per meter between the two wires of a jumper cable being used to start a stalled car is 0.244 N/m. (a) What is the current (in A) in the wires, given they are separated by 1.70 cm

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  1. 15 July, 14:02
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    Answer: current I is 144amp (A)

    Explanation: The force per lenght F/L, current l, and separation distance r are related by the formula

    F/L = permeability of space * I²/2*pi*r

    Permeability of free space is 1.257*EXP {-6} Henry/meter

    F/L is 0.244 N/m, pi is 3.142,

    r is 1.7cm which is equal to 0.017meter.

    I is what we are looking for.

    Now we have after substitution,

    0.244

    = 1.257*EXP {-6} * I² / (2*3.142*0.017)

    After cross multiplying and making I² subject of formula we have,

    0.0261 / (1.257*EXP {-6}) = I²

    I = √{20736.7} = 144ampere (A)

    That means in each of the jumper wire there is 144amp (A)
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