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12 July, 01:01

A projectile is shot from the edge of a cliff 160 m above ground with an initial speed of 55.0 m/s at an angle of 40° below the horizontal. How much time does it take the projectile to hit the ground?

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  1. 12 July, 01:29
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    Time of flight = 3.61secs

    Explanation:

    To find time the projectile hits the ground we must find maximum height

    H = U^2sin^2theta/2g

    H = 55^2*sin^240°/2*9.8

    H = 3025*0.4132/19.6 = 63.77

    T = sqrt (2H/g) =

    T = sqrt 55*2/9.8

    T = sqrt13.05

    T = 3.61secs
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