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25 September, 07:09

You are given two positively charged particles, of equal magnitude, separated by a distance, "d". What will happen to the force field between the two particles when "d" is doubled?

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Answers (2)
  1. 25 September, 10:07
    0
    c

    Explanation:

    because i look up the answer
  2. 25 September, 10:10
    0
    Force becomes 1/4th

    Explanation:

    Force between two positively charged particles is given by the equation

    F = k*q1*q2/r² So, force is inversely proportional to square of r.

    Here, k is a constant, q1 and q2 are the charges which are equal and r is the distance between them.

    So if the distance is doubled, r becomes 2r and r² becomes (2r) ² = 4r² Force, F then becomes 1/4th of the initial force.
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