Jack and Jill are maneuvering a 3100 kg boat near a dock. Initially the boat's position is m and its speed is 1.6 m/s. As the boat moves to position m, Jack exerts a force of N, and Jill exerts a force of N.

How much work does Jack do?

How much work does Jill do?

(a) work done by Jack is - 2200J

(b) work done by Jill is 0

Explanation:

Given;

Initially boat's position = m

Final boat's position = m

change in position =

Force exerted by Jack = N

Force exerted by Jill = N

Part (a) How much work does Jack do?

work done = force x distance

Jack's work = N x m

= [ (-440*4) + (0*0) + (220*-2) ]

= - 1760 J - 440 J

= - 2200J

Part (b) How much work does Jill do?

Jill's work = N x m

= [ (170*4) + (0*0) + (340*-2) ]

= 680 J - 680 J

= 0