Determine the period of a 1.7-m-long pendulum on the Moon, where the free-fall acceleration is 1.624 m/s2. Express your answer with the appropriate units.

Question

Physics

Bentley

3 May, 02:10

Determine the period of a 1.7-m-long pendulum on the Moon, where the free-fall acceleration is 1.624 m/s2. Express your answer with the appropriate units.

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Answers (1)

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Brayan Cunningham · Answer 1

6.42 s

Explanation:

Period: This can be defined as the time taken for a wave or an oscillating body to complete on oscillation. The S. I unit of period is Second (s).

The period of a simple pendulum is represented as,

T = 2π√ (L/g) ... Equation 1.

Where T = period, L = length of the pendulum, g = acceleration due to gravity. π = pie.

Given: L = 1.7 m, g = 1.624 m/s² and π = 3.14

T = 2 (3.14) √ (1.7/1.624)

T = 6.28√ (1.047)

T = 6.28*1.023

T = 6.42 s.

Thus, the period of the pendulum = 6.42 s