A certain metal with atomic mass 2.4 * 10-25 kg has an interatomic bond with length 2.4 * 10-10 m and stiffness 45 N/m. What is the speed of sound in a rod made of this metal?

Given Information:

Stiffness of the metal = s = 45 N/m

Atomic mass of the metal = m = 2.4*10⁻²⁵ kg

Interatomic bond distance = d = 2.4*10⁻¹⁰ m

Required Information:

Speed of sound = v = ?

Answer:

v = 3286.3 m/s

Explanation:

The speed of the sound in a rod made of this metal can be found using the following equation

v = √ (s/m) * d

Where s is the stiffness of the metal, m is the atomic mass of the metal, and d is the interatomic bond distance

v = √ (45/2.4*10⁻²⁵) * (2.4*10⁻¹⁰)

v = 3286.3 m/s

Therefore, the speed of the sound in a rod made of this metal would be 3286.3 m/s