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12 September, 13:07

An oxygen atom (mass 16 u) moving at 733 m/s at 15.0^/circ15.0 ∘ with respect to the / hat{i} i ^ direction collides and sticks to an oxygen molecule (mass 32 u) moving at 528 m/s at 128^/circ128 ∘ with respect to the / hat{i} i ^ direction. The two stick together to form ozone. What is the direction of the final velocity of the ozone molecule?

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  1. 12 September, 14:13
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    Representing the velocity of oxygen atom in vector form

    v₁ = 733 cos 15 i + 733 sin15 j

    = 708 i + 189.7 j

    Similarly velocity of oxygen molecule

    = 528 cos 128 i + 528 sin128 j

    = - 325 i + 416 j

    Applying conservation of momentum

    m₁ v₁ + m₂v₂ = (m₁ + m₂) v

    16 (708 i + 189.7 j) + 32 (-325 i + 416 j) = 48 v

    11328 i + 3035.2 j - 10400 i + 13312 j = 48 v

    928 i + 16347.2 j = 48 v

    v = 19.33 i + 340.56 j

    angle of this vector

    tanθ = 340.56 / 19.33

    = 17.61

    87 °
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