A car with an initial speed of 25 m/sec accelerates at a uniform rate of 0.92 m/s2 for 3.6 s. Find the final speed

and the displacement of the car during this time.

28 m/s

96 m

Explanation:

Given:

v₀ = 25 m/s

a = 0.92 m/s²

t = 3.6 s

Find: v and Δx

v = at + v₀

v = (0.92 m/s²) (3.6 s) + (25 m/s)

v = 28.3 m/s

Δx = v₀ t + ½ at²

Δx = (25 m/s) (3.6 s) + ½ (0.92 m/s²) (3.6 s) ²

Δx = 96.0 m

Rounded to two significant figures, the final speed and displacement are 28 m/s and 96 m.