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8 March, 23:43

A 45.0 kg skier testing a new competitive ski wax drops off a ledge, goes into a crouch and goes straight down a slope of 10.0◦ with respect to the horizontal. The coefficient of kinetic friction between the snow and skis is 0.114. The skier's speed after traveling 300 m along this slope is (in m/s) :

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  1. 9 March, 01:40
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    v = 21.03 m/s

    Explanation:

    given,

    mass of skier = 45 kg

    the slope of the snow = 10.0◦

    coefficient of friction = 0.114

    distance traveled = 300 m

    speed = ?

    Acceleration = g sin θ - µ g Cos θ

    = 9.8 * Sin (10°) - 0.10 * 9.8 * Cos (10°)

    = 0.737 m/s²

    using equation of motion

    v² = u² + 2 a s

    v² = 0 + 2 * 0.737 * 300

    v = 21.03 m/s

    Speed of skier's after travelling 300 m speed is equal to 21.03 m/s
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