Two long, parallel wires are separated by 2.0 m. Each wire has a 28-A current, but the currents are in opposite directions. Part A Determine the magnitude of the net magnetic field midway between the wires. Express your answer with the appropriate units. B

Given Information:

Current = I = 28 A

distance between wires = r = 2.0 m

Required Information:

Magnetic field = B = ?

Answer:

B = 12x10⁻⁶ T

Step-by-step explanation:

Biot-Savart Law is given by

B = μ₀I/2πr

Where μ₀ is the permeability of free space, I is the current flowing through the wire and B is the magnitude of the magnetic field produced.

We are asked to find the magnetic field midway between the wires so r/2 = 1

B = 4πx10⁻⁷*28/2π*1

B = 6x10⁻⁶ T

since the same amount of current flows in both wires therefore, equal amount of magnetic field will be produced in both wires

B = 2*6x10⁻⁶ T

B = 12x10⁻⁶ T

Therefore, the net magnetic field midway between the two wires is 12x10⁻⁶ T.