15 J of work were expended moving an 18 kg block. At what velocity did the block move?

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Answer:√ (5/3) m/s

Explanation:

Kinetic energy (ke) = 15joules

Mass (m) = 18kg

Velocity (v) = ?

Ke = (mxv^2) ➗ 2

15 = (18xv^2) ➗ 2

Cross product

(18xv^2) = 15x2

18xv^2=30

Divide both sides by 18

(18xv^2) / 18=30/18

v^2=5/3

v=√ (5/3)

v=√ (5/3) m/s

1.29m/s

Explanation:

Since work and energy have same unit of measurement, then

kinetic energy of the block = 15J

M = 18kg

V = ?

K. E = 1/2MV^2

V^2 = 2K. E / M

V^2 = (2 x 15) / 18

Take the square root of both side

V = √[ (2 x 15) / 18]

V = 1.29m/s

The block moved with a velocity of 1.29m/s