Air conditioners sold in the United States are given a seasonal energy-efficiency ratio (SEER) rating that consumers can use to compare different models. A SEER rating is the ratio of heat pumped to energy input, similar to a COP but using English units, so a higher SEER rating means a more efficient model. You can determine the COP of an air conditioner by dividing the SEER rating by 3.4For inside temperature 25? C and outside temperature 34? C when you'd be using air conditioning, estimate the theoretical maximum SEERrating of an air conditioner. (New air conditioners must have a SEER rating that exceeds 13, quite a bit less than the theoretical maximum, but there are practical issues that reduce efficiency.)

112.58

Explanation:

The Coefficient of Performance of any system is denoted by COP=Q/W, where Q is the useful heat supplied or removed and W is the work required by the system. According to the first law of thermoddynamics Qh = Qc + W, where Qh is the heat transfered to the hot reservoir and Qc is the heat collected from the cold reservoir. Substituting the values for W and apllying the limitation for maximum theoretical efficiency we end up with the eqution shown below.

The Coefficient of Performance of air conditioner or COP is denoted by

COP (cool) = Tc / (Th - Tc)

where Tc: the lowest temperature

Th: the highest temperature

converting the values to Kelvin and adding them in the above equation

COP (cool) = (25+273) / ((34+273) - (25+273))

= 298 / (307-298)

= 298/9 = 33.11

From the question, it is stated that COP=SEER/3.4

hence, SEER = COP * 3.4

SEER = 33.11 * 3.4 = 112.58