A weight lifter lifts a 300-N set of weights from ground level to a position over his head, a vertical distance of 2.15 m. How much work does the weight lifter do, assuming he moves the weights at constant speed

W = 645 J

Explanation:

The work done on an object is equal to the product of the force applied on the object and the distance through which it moves.

W = F d

where,

W = Work Done

F = Force

d = Displacement

In this case, the variables are as follows:

F = Weight of Sets = 300 N

d = vertical distance covered = 2.15 m

Therefore,

W = (300 N) (2.15 m)

W = 645 J