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28 April, 15:30

A crate of mass 9.2 kg is pulled up a rough incline with an initial speed of 1.42 m/s. The pulling force is 94 N parallel to the incline, which makes an angle of 19.6° with the horizontal. The coefficient of kinetic friction is 0.400, and the crate is pulled 4.92 m. (a) How much work is done by the gravitational force on the crate?.

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  1. 28 April, 17:31
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    W = - 148.8 J

    Explanation:

    given,

    mass = 9.2 kg

    initial speed = 1.42 m/s

    pulling force = 94 N

    angle θ = 19.6°

    coefficient of kinetic friction = 0.400

    the crate is pulled = 4.92 m

    to calculate of work done by the gravitation force

    gravitation force

    W = (m g sin θ) x

    W = 9.2 * (-9.8) * sin 19.6° * 4.92

    W = - 148.8 J

    Work done by the gravitation force is taken as negative because gravitation force act opposite to the force applied.
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