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12 June, 17:45

An object is being acted upon by three forces and moves with a constant velocity. One force is 60.0 N along the x-axis, the second in 75.0 N along the y-axis. What is the magnitude of the third force?

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  1. 12 June, 18:09
    0
    96.05 N

    Explanation:

    From Vector,

    The two forces acting along the x and y axis are perpendicular,

    Fr = √ (60²+75²) ... Equation 1

    Where Fr is the result of the two forces

    Fr = √ (3600+5625)

    Fr = √ (9225)

    Fr = 96.05 N.

    Note: Since the object moves with a constant velocity when it is acted upon by the three forces, The acceleration is zero and as such the resultant of the forces is equal to zero.

    Therefore,

    Ft = Fr+F3 ... Equation 2

    Where Ft = Total resistance of the three forces, F3 = magnitude of the third force.

    make F3 the subject of the equation,

    F3 = Ft-Fr

    Given: Ft = 0 N, Fr = 96.05 N.

    Substitute into equation 2

    F3 = 0-96.05

    F3 = - 96.05 N.
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