A 0.50 kg croquet ball is initially at rest on the grass. When theball is struck by a mallet, the average force exerted on it is240 N. If the ball's speed after beingstruck is 3.0 m/s, how long was the malletin contact with the ball?

time=6.25*10⁻³ seconds

or

time=6.25 Milliseconds

Explanation:

Given Data

Ball mass = 0.50 kg

Force = 240 N

Speed = 3.0 m/s

To find

Time

Solution

From Newtons second Law of motion

Force=mass*acceleration

As mass and Force is given we need to Find acceleration

So

Acceleration=Force/mass

Acceleration=240/0.50

Acceleration=480 m/s²

When ball was at rest its velocity at that time was 0. Now the final velocity is given as:

Velocity=acceleration*time

As we have find the acceleration and velocity is given so we can find time easily

So

time=velocity/acceleration

time = (3.0m/s) / 480 N

time=6.25*10⁻³ seconds

or

time=6.25 Milliseconds