6. Two positive charges, each with 6.0 x 10^-6 C, are 0.75 meters apart.

What force exists between the two charges?

Answer: F = 5.76x10^-1 N

Explanation:

The force between two charges is:

F = k*q1*q2/r^2

where k = 9x10^9 N*m^2/C^2 is the Coulomb's constant.

q1 and q2 = 6x10^-6 C

and r is the distance between the charges, here r = 0.75m

then the force is:

F = (9x10^9 N*m^2/C^2) * 6x10^-6 C*6x10^-6 C / (0.75m) ^2 = 576x10^-3 N

F = 5.76x10^-1 N

We have a positive force, this means that we have a repulsive force.