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8 August, 20:23

A rectangular wooden block of weight W floats with exactly one-half of its volume below the waterline. Masses are stacked on top of the block until the top of the block is level with the waterline. This requires 20 g of mass. What is the mass of the wooden block? A.) 40 gB.) 20 gC.) 10 g

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  1. 8 August, 23:14
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    b) M=20g

    Explanation:

    For this exercise we must use the Archimedes principle that states that the thrust that a body receives is equal to the weight of the dislodged liquid.

    B = ρ g V

    Let's use balance healing for this case

    Initial.

    B - W = 0

    The weight of the body can be related to its density

    W = ρ V_body g

    ρ_liq g (½ V_body) = m g

    Final

    Some masses were added

    M = 20 g = 0.020 kg

    B - W - W₂ = 0

    ρ_liq g V_Body = m g + M g

    Let's replace and write the system of equations

    ½ ρ_liq V_body = m

    ρ V_body = m + M

    We solve the equations

    2 m = m + M

    m = M

    m = 20 g

    The answer is b
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