A toy car runs off the edge of a table that is 2.225 m high. If the car lands 0.400 m away from the base of the table, how fast was the car going when it fell off?

0.594 m/s

Explanation:

First, find the time it takes to land.

Given, in the y direction:

Δy = 2.225 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(2.225 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 0.674 s

Next, find the horizontal velocity.

Given, in the x direction:

Δx = 0.400 m

a = 0 m/s²

t = 0.674 s

Find: v₀

Δx = v₀ t + ½ at²

(0.400 m) = v₀ (0.674 s) + ½ (0 m/s²) (0.674 s) ²

v₀ = 0.594 m/s