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17 May, 12:47

Due to gravity, the rock strikes the ground at a horizontal distance of 18.1 m from the base of the building. Building 18.1 m 59 ◦ 11.9 m/s h How tall is the building? Assume the ground is level and that the side of the building is vertical. The acceleration of gravity is 9.8 m/s 2. Answer in units of m.

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  1. 17 May, 16:32
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    The building is 12.56 m tall

    Explanation:

    Horizontal velocity = 11.9 x cos 59 = 6.13 m/s

    Vertical velocity = 11.9 x sin 59 = 10.2 m/s

    Horizontal distance traveled = 18.1 m

    Consider the horizontal motion of rock,

    We have equation of motion, s = ut + 0.5at²

    Initial velocity, u = 6.13 m/s

    Acceleration, a = 0 m/s²

    Displacement, s = 18.1 m

    Substituting,

    s = ut + 0.5at²

    18.1 = 6.13 x t + 0.5 x 0 x t²

    t = 2.95 s

    Consider the vertical motion of rock,

    We have equation of motion, s = ut + 0.5at²

    Initial velocity, u = 10.2 m/s

    Acceleration, a = - 9.81 m/s²

    Displacement, s = Negative of height = - h

    Time, t = 2.95 s

    Substituting,

    s = ut + 0.5at²

    -h = 10.2 x 2.95 + 0.5 x (-9.81) x 2.95²

    h = 12.56 m

    The building is 12.56 m tall
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