If three of 3 ohms, 5 ohms, and 22 ohms are connected in series in a 28-volt circuit, how much current will flow through the 3-ohm resistor? A - 9.3 amperesB - 1.05 amperesC - 0.93 amperes

Option C is the correct answer.

Explanation:

We know that in series connection current in all the resistors are same.

Effective resistance is sum of individual resistances.

Here three of 3 ohms, 5 ohms, and 22 ohms are connected in series in a 28-volt circuit

Effective resistance = 3 + 5 + 22 = 30 ohms

Voltage = 28 V

We know

Voltage = Current x Resistance

V = IR

28 = 30 x I

I = 0.93 A

Current in each resistor is 0.93 A

Option C is the correct answer.