A bullet is fired vertically upward from a gun with an initial velocity of 225 m/s. How high does the bullet go in meters? [Ignore air resistance]

h = 2582.9 m

Explanation:

bullet kinematics: bullet moves with uniformly accelerated movement in freefall

The negative sign in the equation indicates that the acceleration (g) is in the direction opposite to the movement of the bullet.

v f₁²=v₀²-2g*h₁ Equation (1))

h: hight in meters (m)

v₀: initial speed in m/s

vf: final speed in m/s

Known data

v₀ = 225 m/s

g = 9.8 m/s² : acceleration due to gravity

Problem development

When the bulletl reaches the maximum height the final speed is equal to zero. vf=0

We replace data in the equation (1)

v f₁²=v₀²-2g*h₁

0 = (225) ²-2*9.8*h

2*9.8*h = (225) ²

h = (225) ² / (2*9.8)

h = 2582.9 m