An astronaut standing on a platform on the Moon drops a hammer. If the hammer falls 6.0 meters vertically in 2.7 seconds, what is its acceleration? a. 1.6m/s²

b. 4.4m/s²

c. 2.2m/s²

d. 9.8m/s²

Option A is the correct answer.

Explanation:

We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 0 m/s

Acceleration, a = ?

Displacement, s = 6 m

Time, t = 2.7 s

Substituting

s = ut + 0.5 at²

6 = 0 x 2.7 + 0.5 x a x 2.7²

a = 1.65 m/s²

Acceleration is 1.65 m/s²

Option A is the correct answer.