An automobile is depreciating at 11% per year, every year. A $30,000 car depreciating at this rate can be modeled by the equation V (t) = 30,000 (0.89) t. What is an equivalent equation for this vehicle at a daily depreciation and what is it worth (rounded to the nearest thousand dollar) 5 years after purchase?

a. V (t/365) = 30,000 (0.89) ^ (t/365).

b. V (5) = $17000

Explanation:

An automobile is depreciating at 11% per year, every year. A $30,000 car depreciating at this rate can be modeled by the equation V (t) = 30,000 (0.89) t. What is an equivalent equation for this vehicle at a daily depreciation and what is it worth (rounded to the nearest thousand dollar) 5 years after purchase?

i will like to work back from te question by solving questin 2 first

V (t) = 30,000 (0.89) ^t

let t=5

V (5) = 30,000 (0.89) ^5

V (5) = $17000

2. yearly depreciation will be

30,000 (0.89) ^1

26700=it amounts to tis after a year,

so it depreciates by 3300 for one year

daily depreciation will be 3300/365,

since there are 365 days in a year

$9.041

the equation that satisfy this is

V (t/365) = 30,000 (0.89) ^ (t/365).