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26 May, 01:32

A 6.0 mw vertically polarized laser beam passes through a polarizing filter whose axis is 75° from vertical. What is the laser-beam power after passing through the filter?

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  1. 26 May, 05:14
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    I = 0.4019 m W

    Explanation:

    given,

    Beam of light Intensity = 6.0 m W

    angle made with the vertical = 75°

    Power of the laser beam passing through filter = ?

    using formula

    I = I₀ cos² (θ)

    I is the intensity required

    I₀ is the initial intensity of light

    I = I₀ cos² (θ)

    I = 6 x cos² (75°)

    I = 6 x 0.0669

    I = 0.4019 m W

    Laser beam power after passing through filter is equal to I = 0.4019 m W
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