Ask Question
19 August, 16:12

a 1500.0 kg car is at rest on a level track. The driver gives the engine gas and the car begins to accelerate forward. The car moves from 0 m/s to 27 m/s in 8 s. What is the acceleration of the car. What is the force of the car moving forward?

+4
Answers (1)
  1. 19 August, 16:45
    0
    Acceleration of the car is 3.375 m/s² and the force of the car moving forward is 5062.5 N

    Explanation:

    Acceleration is the rate of change of velocity. It is given by the equation, a = change in velocity/time

    Here, velocity changes from 0 to 27 m/s and time = 8

    ⇒ Acceleration = 27 - 0/8 = 27/8 = 3.375 m/s²

    Force is calculated by the equation, F = Mass * Acceleration This is based on Newton's second law of motion.

    Here, mass of the car = 1500 kg and a = 3.375 m/s²

    ⇒ Force = 1500 * 3.375 = 5062.5 N
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “a 1500.0 kg car is at rest on a level track. The driver gives the engine gas and the car begins to accelerate forward. The car moves from 0 ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers