In addition to their remarkable top speeds of almost 60 mph, cheetahs have impressive cornering abilities. In one study, the maximum centripetal acceleration of a cheetah was measured to be 17 m/s2. What minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?

coefficient of static friction is 1.7329

Explanation:

given data

velocity = 60 mph

acceleration = 17 m/s²

to find out

coefficient of static friction

solution

we will apply here centripetal force equation

that is

m*v²/r = µ * m * g ... 1

here v²/r is centripetal acceleration and m is mass and µ is coefficient static friction so

µ = a / g

µ = 17 / 9.81

µ = 1.7329

so coefficient of static friction is 1.7329