Ask Question
30 June, 11:02

For a certain driven series RLC circuit, the maximum generator emf is 156 V and the maximum current is 3.32 A. The current leads the generator emf by 0.959 rad. (a) What is the impedance of the circuit?

+5
Answers (1)
  1. 30 June, 11:46
    0
    Z=76.6 + j46.7

    Explanation:

    angle between Voltage and current: ∅=0.959

    Impedence is given by:

    V=IZ

    Z = V / (Icos∅ + j Isin∅)

    Z = 156 / (3.32 ∠ 0.96)

    Z=76.6 + j46.7
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “For a certain driven series RLC circuit, the maximum generator emf is 156 V and the maximum current is 3.32 A. The current leads the ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers